extreme F(x)=x^3-5x^2-8x+4

Lösung

extrempunkte

F (x) = x^{3} - 5 x^{2} - 8 x + 4

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 10 x - 8

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < 4,

Ansteigend

: 4 < x < \infty

Stecke

x = - \frac{2}{3}

x^{3} - 5 x^{2} - 8 x + 4 : \frac{184}{27}

Maximum (- \frac{2}{3}, \frac{184}{27})

Stecke

x = 4

x^{3} - 5 x^{2} - 8 x + 4 : - 44

Minimum (4, - 44)

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

r an g e f (x) = \frac{2 x ^{2} - 3}{x ^{2} - 1}

in v erse f (x) = - \frac{6}{x}

in v erse f (x) = \frac{x - 3}{4}

in v erse y = \frac{- 5}{1.25} (x - 8.5) + 7

in t erce pt s 3 x^{3} - 4 x^{2} + 3 x - 2