What is the inverse of f(x)=(4-x^2)/2 ?

The inverse of f(x)=(4-x^2)/2 is sqrt(-2x+4),-sqrt(-2x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(4-x^2)/2

inverse

f (x) = \frac{4 - x ^{2}}{2}

- 2 x + 4, - - 2 x + 4

Solution steps

y = \frac{4 - x ^{2}}{2}

Replace

x

with

y

x = \frac{4 - y ^{2}}{2}

Solve for

y, x = \frac{4 - y ^{2}}{2}

- 2 x + 4, - - 2 x + 4

f (x) = 2 - \frac{6}{5} x

f (x) = \frac{4 x - 5}{2 x + 1}

2 x^{\frac{1}{2}}

y = 16 - x^{2}

f (x) = \frac{5}{6 x + 1}

What is the inverse of f(x)=(4-x^2)/2 ?
The inverse of f(x)=(4-x^2)/2 is sqrt(-2x+4),-sqrt(-2x+4)