What is the inverse of y=log_{5}(x)+log_{5}(7) ?

The inverse of y=log_{5}(x)+log_{5}(7) is 1/7*5^x

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inverse of y=log_{5}(x)+log_{5}(7)

inverse

y = lo g_{5} (x) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

Solution steps

y = lo g_{5} (x) + lo g_{5} (7)

Replace

x

with

y

x = lo g_{5} (y) + lo g_{5} (7)

Solve for

y, x = lo g_{5} (y) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

f (x) = x^{2} - 9, x \geq 3

2^{1 + \frac{1}{2}} x^{\frac{3}{2}}

f (x) = 2 (3^{x}) + 1

f (x) = - 13 x - 9

3 x + 9

What is the inverse of y=log_{5}(x)+log_{5}(7) ?
The inverse of y=log_{5}(x)+log_{5}(7) is 1/7*5^x