What is the inverse of f(x)=3(x+2)^3-1 ?

The inverse of f(x)=3(x+2)^3-1 is \sqrt[3]{(x+1)/3}-2

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inverse of f(x)=3(x+2)^3-1

inverse

f (x) = 3 (x + 2)^{3} - 1

Solution steps

y = 3 (x + 2)^{3} - 1

Replace

x

with

y

x = 3 (y + 2)^{3} - 1

Solve for

y, x = 3 (y + 2)^{3} - 1

\frac{1}{x} + 2

\frac{1}{x} + 4

f (x) = x^{\frac{3}{5}} + 2

\frac{a ( s ^{2} - 2 a ^{2} )}{s ^{4} + 4 a ^{4}}

f (x) = \frac{- 9 - 7 x}{8}

What is the inverse of f(x)=3(x+2)^3-1 ?
The inverse of f(x)=3(x+2)^3-1 is \sqrt[3]{(x+1)/3}-2