What is the inverse of f(x)=\sqrt[3]{x-2}+5 ?

The inverse of f(x)=\sqrt[3]{x-2}+5 is x^3-15x^2+75x-123

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inverse of f(x)=\sqrt[3]{x-2}+5

inverse

f (x) = 3 x - 2 + 5

x^{3} - 15 x^{2} + 75 x - 123

Solution steps

y = 3 x - 2 + 5

Replace

x

with

y

x = 3 y - 2 + 5

Solve for

y, x = 3 y - 2 + 5

x^{3} - 15 x^{2} + 75 x - 123

f (x) = (0.2)

f (x) = (x + 6)^{2} - 2

f (x) = 0.95

y = \frac{3 x}{( 1 - 2 x )}

f (x) = - 16 x + 4

What is the inverse of f(x)=\sqrt[3]{x-2}+5 ?
The inverse of f(x)=\sqrt[3]{x-2}+5 is x^3-15x^2+75x-123