求反函数 f(x)=140-4.9t^2

解答

求反函数

f (x) = 140 - 4.9 t^{2}

- \frac{10 t - 1400}{49}, - - \frac{10 t - 1400}{49}

求解步骤

x = 140 - 4.9 t^{2}

用

x

替代

t

t = 140 - 4.9 x^{2}

求解

x, t = 140 - 4.9 x^{2}

- \frac{10 t - 1400}{49}, - - \frac{10 t - 1400}{49}

in v erse arctan (e^{2 x})

in v erse f (59) = x^{3} - 5

in v erse f (x) = \frac{4 x}{3}

in v erse f (x) = \frac{1}{4} \cdot 1 0^{x - 3} + 5

in v erse f (x) = \frac{- 2 x - 1}{x - 2}