What is the inverse of f(x)=8x^2-4 ?

The inverse of f(x)=8x^2-4 is (sqrt(2)sqrt(x+4))/4 ,-(sqrt(2)sqrt(x+4))/4

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inverse of f(x)=8x^2-4

inverse

f (x) = 8 x^{2} - 4

\frac{2 x + 4}{4}, - \frac{2 x + 4}{4}

Solution steps

y = 8 x^{2} - 4

Replace

x

with

y

x = 8 y^{2} - 4

Solve for

y, x = 8 y^{2} - 4

\frac{2 x + 4}{4}, - \frac{2 x + 4}{4}

(x - 4)^{2} + 7

f (x) = \frac{9 x + 6}{x + 8}

f (x) = - 4 (x - 2)^{2} + 6

f (x) = \frac{9 x + 27}{x - 12}

f (x) = x^{2} - 4 x + 5, x \geq 2

What is the inverse of f(x)=8x^2-4 ?
The inverse of f(x)=8x^2-4 is (sqrt(2)sqrt(x+4))/4 ,-(sqrt(2)sqrt(x+4))/4