What is the inverse of f(-1)=(3-2x)/(2x-5) ?

The inverse of f(-1)=(3-2x)/(2x-5) is (3+5x)/(2(1+x))

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inverse of f(-1)=(3-2x)/(2x-5)

inverse

f (- 1) = \frac{3 - 2 x}{2 x - 5}

\frac{3 + 5 x}{2 ( 1 + x )}

Solution steps

y = \frac{3 - 2 x}{2 x - 5}

Replace

x

with

y

x = \frac{3 - 2 y}{2 y - 5}

Solve for

y, x = \frac{3 - 2 y}{2 y - 5}

\frac{3 + 5 x}{2 ( 1 + x )}

f (x) = 3 \cdot + 1

f (x) = 3 x - 6 + 5

f (y) = x^{2} - 20 x + 100

f (x) = \frac{( x + 10 )}{3 x}

f (x) = (x + 1) (x - 5)

What is the inverse of f(-1)=(3-2x)/(2x-5) ?
The inverse of f(-1)=(3-2x)/(2x-5) is (3+5x)/(2(1+x))