What is the inverse of f(x)=3x^2-x+3 ?

The inverse of f(x)=3x^2-x+3 is (1+sqrt(12x-35))/6 ,(1-sqrt(12x-35))/6

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inverse of f(x)=3x^2-x+3

inverse

f (x) = 3 x^{2} - x + 3

\frac{1 + 12 x - 35}{6}, \frac{1 - 12 x - 35}{6}

Solution steps

y = 3 x^{2} - x + 3

Replace

x

with

y

x = 3 y^{2} - y + 3

Solve for

y, x = 3 y^{2} - y + 3

\frac{1 + 12 x - 35}{6}, \frac{1 - 12 x - 35}{6}

h (x) = 7 x - 5

f (x) = 3 + \frac{5}{2} x

f (x) = \frac{3 x - 5}{2}

y = \frac{( 7 x - 2 )}{( 4 x + 5 )}

What is the inverse of f(x)=3x^2-x+3 ?
The inverse of f(x)=3x^2-x+3 is (1+sqrt(12x-35))/6 ,(1-sqrt(12x-35))/6