What is the domain of f(x)=((sqrt(4+3x-x^2)))/(3x+5) ?

The domain of f(x)=((sqrt(4+3x-x^2)))/(3x+5) is -1<= x<= 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((sqrt(4+3x-x^2)))/(3x+5)

domain

f (x) = \frac{( 4 + 3 x - x ^{2} )}{3 x + 5}

- 1 \leq x \leq 4

Interval Notation

[- 1, 4]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 4

Find undefined (singularity) points:

x = - \frac{5}{3}

Combine real regions and undefined points for final function domain

- 1 \leq x \leq 4

f (x) = \frac{x ^{2} - 25}{x ^{2} - 11 x + 18}

\frac{2}{x + 2}

2 x^{3} + 9 x

f (x) = 50 - x^{2}

f (x) = - \frac{25}{( t + 4 ) ^{2}}

What is the domain of f(x)=((sqrt(4+3x-x^2)))/(3x+5) ?
The domain of f(x)=((sqrt(4+3x-x^2)))/(3x+5) is -1<= x<= 4