What is the domain of f(x)=1+ln(sqrt(x-1)) ?

The domain of f(x)=1+ln(sqrt(x-1)) is x>1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=1+ln(sqrt(x-1))

domain

f (x) = 1 + ln (x - 1)

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

f (x) = 2 (2^{x})

\frac{1}{x} - 7

f (x) = x + \frac{x}{x - 2} + 1

- 3 x^{2}

f (x) = \frac{7}{2 x - 1}

What is the domain of f(x)=1+ln(sqrt(x-1)) ?
The domain of f(x)=1+ln(sqrt(x-1)) is x>1