What is the domain of sqrt((x^2-2x-48)/(x-1)) ?

The domain of sqrt((x^2-2x-48)/(x-1)) is -6 = 8

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domain of sqrt((x^2-2x-48)/(x-1))

domain

\frac{x ^{2} - 2 x - 48}{x - 1}

- 6 \leq x < 1 or x \geq 8

Interval Notation

Solution steps

Find non-negative values for radicals:

- 6 \leq x < 1 or x \geq 8

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 6 \leq x < 1 or x \geq 8

f (x) = 3 x^{2} + 13 x + 14

\frac{2 x - 3}{x - 2}

f (x) = 1 - 2 cos (\frac{x}{3} + \frac{2 π}{3})

f (x) = 11 - 2 x

\frac{x + 4}{3 x + 1}

What is the domain of sqrt((x^2-2x-48)/(x-1)) ?
The domain of sqrt((x^2-2x-48)/(x-1)) is -6<= x<1\lor x>= 8