What is the domain of f(x)=(9+x)/(1-9x) ?

The domain of f(x)=(9+x)/(1-9x) is x 1/9

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domain of f(x)=(9+x)/(1-9x)

domain

f (x) = \frac{9 + x}{1 - 9 x}

x < \frac{1}{9} or x > \frac{1}{9}

Interval Notation

(- \infty, \frac{1}{9}) \cup (\frac{1}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{9}

The function domain

x < \frac{1}{9} or x > \frac{1}{9}

f (x) = \frac{x}{e ^{x^{2} \cdot 5 x + 6}} + ln (x - 1)

\frac{( x + 2 ) ( x - 3 )}{x ^{2} - 4}

\frac{x - 6}{x ^{2} + 12 x + 36}

(x + 3) - 2

f (x) = arcsin (\frac{2 x + 1}{x} - 1)

What is the domain of f(x)=(9+x)/(1-9x) ?
The domain of f(x)=(9+x)/(1-9x) is x< 1/9 \lor x> 1/9