频率 f(x)= 1/2 cos(2x)

解答

频率

f (x) = \frac{1}{2} cos (2 x)

\frac{1}{π}

十进制

0.31830 \dots

求解步骤

f (x) = \frac{1}{2} cos (2 x)

g (B x - C) = cos (2 x), B = 2

\frac{B}{2 π} = \frac{2}{2 π}

\frac{1}{π}

d o main f (t) = 17 - 1.2 t

d o main x^{2} + 2 x - 5

p a r i t y y = ln (x^{4} sin^{2} (x))

d o main f (x) = lo g_{3} (x) + 6

in t erce pt s \frac{1}{4} x^{3} - 6