定义域 ln(-x^2+3x+10)

解答

定义域

ln (- x^{2} + 3 x + 10)

- 2 < x < 5

间隔符号

(- 2, 5)

求解步骤

对于对数找到正值:

- 2 < x < 5

函数定义域

- 2 < x < 5

d o main f (x) = \frac{1}{x ^{2}} + 3

d o main f (x) = 1 + e^{(\frac{x ^{2}}{∣ x ∣ - 2})}

d o main g (x) = 6 - \frac{1}{x ^{2}}

d o main f (x) = \frac{9}{x - 13} + \frac{3}{x - 2}

d o main (x + 5) - (x^{2} + 8 x)