What is the domain of f(x)=x^2-5*sqrt(x-4) ?

The domain of f(x)=x^2-5*sqrt(x-4) is x>= 4

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domain of f(x)=x^2-5*sqrt(x-4)

domain

f (x) = x^{2} - 5 \cdot x - 4

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

lo g_{10} (x^{3} - 6 x^{2} + 3 x + 10)

y = 2 x^{5} - 3 x^{4} + 5 x - 8

- x - 5 + 4

\frac{x}{2 - x}

f (1) = x - 1

What is the domain of f(x)=x^2-5*sqrt(x-4) ?
The domain of f(x)=x^2-5*sqrt(x-4) is x>= 4