What is the domain of y=(2x^2-3)/(x^2+1) ?

The domain of y=(2x^2-3)/(x^2+1) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(2x^2-3)/(x^2+1)

domain

y = \frac{2 x ^{2} - 3}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{2 x ^{2} + x + 3}{x ^{2} - x - 6}

f (x) = lo g_{8} (x^{2} - 2 x - 48)

ln \frac{x + 2}{x - 1}

r (x) = \frac{x + 2}{x ^{2} - 3 x - 28}

f (x) = \frac{9 x}{∣ x ∣}

What is the domain of y=(2x^2-3)/(x^2+1) ?
The domain of y=(2x^2-3)/(x^2+1) is -infinity <x<infinity