What is the extreme f(x)=4x^3+33x^2-36x-530 ?

The extreme f(x)=4x^3+33x^2-36x-530 is Maximum(-6,10),Minimum(1/2 ,-2157/4)

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extreme f(x)=4x^3+33x^2-36x-530

extreme points

f (x) = 4 x^{3} + 33 x^{2} - 36 x - 530

Maximum (- 6, 10), Minimum (\frac{1}{2}, - \frac{2157}{4})

Solution steps

f^{'} (x) = 12 x^{2} + 66 x - 36

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = - 6

into

4 x^{3} + 33 x^{2} - 36 x - 530 : 10

Maximum (- 6, 10)

Plug

x = \frac{1}{2}

into

4 x^{3} + 33 x^{2} - 36 x - 530 : - \frac{2157}{4}

Minimum (\frac{1}{2}, - \frac{2157}{4})

Maximum (- 6, 10), Minimum (\frac{1}{2}, - \frac{2157}{4})

f (x) = 30 + 20 x^{3} - 5 x^{4} - x^{5}

y = - 2 x^{3} + 540 x^{2}

f (x, y) = x^{3} + 4 y^{2} - 3 x + 1

R (x, y) = - x^{2} - y^{2} + x + 2 y - 1

f (x) = 9 x^{3} - 7 x^{2} + 3 x + 10

What is the extreme f(x)=4x^3+33x^2-36x-530 ?
The extreme f(x)=4x^3+33x^2-36x-530 is Maximum(-6,10),Minimum(1/2 ,-2157/4)