extreme 2x^3-2x+6

Lösung

extrempunkte

2 x^{3} - 2 x + 6

Maximum (- \frac{1}{3}, \frac{4}{3 3} + 6), Minimum (\frac{1}{3}, - \frac{4}{3 3} + 6)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 2

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{3},

Absteigend

: - \frac{1}{3} < x < \frac{1}{3},

Ansteigend

: \frac{1}{3} < x < \infty

Stecke

x = - \frac{1}{3}

2 x^{3} - 2 x + 6 : \frac{4}{3 3} + 6

Maximum (- \frac{1}{3}, \frac{4}{3 3} + 6)

Stecke

x = \frac{1}{3}

2 x^{3} - 2 x + 6 : - \frac{4}{3 3} + 6

Minimum (\frac{1}{3}, - \frac{4}{3 3} + 6)

Maximum (- \frac{1}{3}, \frac{4}{3 3} + 6), Minimum (\frac{1}{3}, - \frac{4}{3 3} + 6)

e x t re m e f (x, y) = x^{2} y + 3 x y^{2}

e x t re m e f (x) = x^{4} + y^{4} - 4 x y + 1

e x t re m e f (x) = \frac{3 x - 6}{x + 2}

e x t re m e f (x, y) = 1 - x^{2} + 2 y^{2}

e x t re m e f (x, y) = 60 x - 2 x^{2} - 3 y^{2} + 30 y