extreme (9x)/(x^2+36)

Lösung

extrempunkte

\frac{9 x}{x ^{2} + 36}

Minimum (- 6, - \frac{3}{4}), Maximum (6, \frac{3}{4})

Schritte zur Lösung

f^{'} (x) = \frac{9 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 6,

Ansteigend

: - 6 < x < 6,

Absteigend

: 6 < x < \infty

Stecke

x = - 6

\frac{9 x}{x ^{2} + 36} : - \frac{3}{4}

Minimum (- 6, - \frac{3}{4})

Stecke

x = 6

\frac{9 x}{x ^{2} + 36} : \frac{3}{4}

Maximum (6, \frac{3}{4})

Minimum (- 6, - \frac{3}{4}), Maximum (6, \frac{3}{4})

e x t re m e f (x) = ln (1 - x) + 10 x

e x t re m e f (x) = 10 - ∣ x ∣

e x t re m e f (x) = - \frac{5}{3} x^{3} + 15 x^{2} + 35 x + 10

e x t re m e f (x, y) = - 4 x + 15 y

e x t re m e y = 1 + x^{2}