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Popular >

extreme f(x)=|x+3|

Solution

extreme points

f (x) = ∣ x + 3 ∣

Solution

Minimum (- 3, 0)

Solution steps

Find the critical points:

x = - 3

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug the extreme point

x = - 3

into

∣ x + 3 ∣ \Rightarrow y = 0

Minimum (- 3, 0)

Graph

Popular Examples

extreme f(x,y)=4x-3y extreme points

f (x, y) = 4 x - 3 y

extreme f(x)=8+81x-3x^3,0<= x<= 4 extreme points

f (x) = 8 + 81 x - 3 x^{3}, 0 \leq x \leq 4

extreme f(x)=x^4-14x^2+49,0<= x<= 5 extreme points

f (x) = x^{4} - 14 x^{2} + 49, 0 \leq x \leq 5

extreme f(x)=ln(x^2+5x+9),-3<= x<= 3 extreme points

f (x) = ln (x^{2} + 5 x + 9), - 3 \leq x \leq 3

extreme x^3-3x^2-24x+8 extreme points

x^{3} - 3 x^{2} - 24 x + 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=|x+3| ?
The extreme f(x)=|x+3| is Minimum(-3,0)