extreme f(x)=x^2-8x+18

Lösung

extrempunkte

f (x) = x^{2} - 8 x + 18

Minimum (4, 2)

Schritte zur Lösung

f^{'} (x) = 2 x - 8

Intervalle finden:

Absteigend

: - \infty < x < 4,

Ansteigend

: 4 < x < \infty

Stecke

x = 4

x^{2} - 8 x + 18 : 2

Minimum (4, 2)

e x t re m e \frac{e ^{x}}{4 + e ^{x}}

e x t re m e f (x, y) = 7 x^{2} + 8 x y + 4 y^{2} + 9 x y^{2} + 8 x^{2} y

e x t re m e y = f (x, y) = - 2 x^{2} - 2 x z - 4 z^{2} + 40 x + 90 z - 150

e x t re m e f (x, y) = (9 x^{2} + 7 x + 10) (9 y^{2} + 4 y + 9)

e x t re m e a + (ln (x))^{2}