extreme y=(4x^2)/(x^2-4)

Lösung

extrempunkte

y = \frac{4 x ^{2}}{x ^{2} - 4}

Maximum (0, 0)

Schritte zur Lösung

f^{'} (x) = - \frac{32 x}{( x ^{2} - 4 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 2,

Ansteigend

: - 2 < x < 0,

Absteigend

: 0 < x < 2,

Absteigend

: 2 < x < \infty

Stecke

x = 0

\frac{4 x ^{2}}{x ^{2} - 4} : 0

Maximum (0, 0)

e x t re m e f (x, y) = x^{3} + 3 x y^{2} - 3 y^{2} + 3 x^{2} + 11

e x t re m e f (x, y) = \frac{1}{3 ^{- x^{2} - y^{2}} + 1}

e x t re m e f (x) = - sin^{2} (x), - π \leq x \leq π

e x t re m e f (x) = x (22 - 40 + 2 x) (\frac{40}{2} - x)

e x t re m e f (x, y) = (y - 8) \cdot x^{2} - y^{2}