extreme f(x)=x^5+243

解答

极值点

f (x) = x^{5} + 243

鞍点 (0, 243)

求解步骤

f^{'} (x) = 5 x^{4}

Find intervals:

递增

: - \infty < x < 0,

递增

: 0 < x < \infty

将

x = 0

代入

x^{5} + 243 : 243

鞍点 (0, 243)

e x t re m e f (x) = 3 x^{2} - 12 x + 7, 0 \leq x \leq 4

e x t re m e (x - 1)^{3} - 3 x

e x t re m e f (x, y) = x^{2} + x y + y^{2} - 6 x

e x t re m e (y^{2} - x^{2}) (y - 2)

e x t re m e f (x) = \frac{x ^{5}}{5} - \frac{4 x ^{4}}{4} + 2