extreme y= 1/(x^2-1)

Lösung

extrempunkte

y = \frac{1}{x ^{2} - 1}

Maximum (0, - 1)

Schritte zur Lösung

f^{'} (x) = - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 1,

Ansteigend

: - 1 < x < 0,

Absteigend

: 0 < x < 1,

Absteigend

: 1 < x < \infty

Stecke

x = 0

\frac{1}{x ^{2} - 1} : - 1

Maximum (0, - 1)

e x t re m e f (x, y) = (x^{2} - 25)^{2} + (y^{2} - 9)^{2}

e x t re m e f (x) = 4 cos (2 x) + 1, (0, 2 π)

e x t re m e 2 x y - 5 x^{2} - 2 y^{2} + 4 x + 4 y - 4

e x t re m e f (x) = x^{2} - 11, - 2 \leq x \leq 4

e x t re m e f (x, y) = x^{2} - 2 x y + y