extreme f(x)=4x+x^2+2

解答

极值点

f (x) = 4 x + x^{2} + 2

极小值 (- 2, - 2)

求解步骤

f^{'} (x) = 2 x + 4

Find intervals:

递减

: - \infty < x < - 2,

递增

: - 2 < x < \infty

将

x = - 2

代入

4 x + x^{2} + 2 : - 2

极小值 (- 2, - 2)

e x t re m e 1 + \frac{7}{x} - \frac{4}{x ^{2}}

e x t re m e x x^{2} + 9

e x t re m e f (x) = \frac{x ^{2} - 4}{x - 1} y

e x t re m e f (x) = 2 + 12 x^{2} - 8 x^{3}

e x t re m e f (x) = x^{2} + y^{2} - 6 x y + 3 x + 6 y - 2