extreme e^{3x^2-x-3}

Lösung

extrempunkte

e^{3 x^{2} - x - 3}

Minimum (\frac{1}{6}, \frac{1}{e ^{\frac{37}{12}}})

Schritte zur Lösung

f^{'} (x) = e^{3 x^{2} - x - 3} (6 x - 1)

Intervalle finden:

Absteigend

: - \infty < x < \frac{1}{6},

Ansteigend

: \frac{1}{6} < x < \infty

Stecke

x = \frac{1}{6}

e^{3 x^{2} - x - 3} : \frac{1}{e ^{\frac{37}{12}}}

Minimum (\frac{1}{6}, \frac{1}{e ^{\frac{37}{12}}})

e x t re m e f (x) = - 2 x^{3} + 18 x^{2} - 30 x, 0 \leq x \leq 6

e x t re m e f (x) = 33 x + 6 cos (x)

e x t re m e f (x) = f (x, y) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

e x t re m e f (x) = x (20 - 39 + 2 x) (\frac{39}{2} - x)

e x t re m e \frac{x ^{2} + 1}{x ^{2} - 9}