extreme f(x)=x^2+((4-x)(4-x))

Lösung

extrempunkte

f (x) = x^{2} + ((4 - x) (4 - x))

Minimum (2, 8)

Schritte zur Lösung

f^{'} (x) = 4 x - 8

Intervalle finden:

Absteigend

: - \infty < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 2

x^{2} + (4 - x) (4 - x) : 8

Minimum (2, 8)

e x t re m e 40000 x + 30000 y - 8 x^{2} - 15 y^{2} - 10 x y

e x t re m e f (x, y) = x^{2} y + y^{2} + 8 x

e x t re m e f (x) = x (15 - 48 + 2 x) (\frac{48}{2} - x)

e x t re m e f (x) = x^{2} + y^{2} + 4 x - 2 y + 6

e x t re m e f (x) = \frac{8 x ^{2}}{x + 1}, (- 1, 5)