extreme f(x)=a+(ln(x))^2

Lösung

extrempunkte

f (x) = a + (ln (x))^{2}

Minimum (1, a)

Schritte zur Lösung

f^{'} (x) = \frac{2 ln ( x )}{x}

Intervalle finden:

Absteigend

: 0 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = 1

a + ln^{2} (x) : a

Minimum (1, a)

e x t re m e x^{2} + x y + y^{2} - 28 y + 261

e x t re m e f (x) = \frac{x ^{\frac{5}{3}}}{2 + x}, - 1 \leq x \leq 8

e x t re m e f (x, y) = x^{2} = x y + y^{2} - 16 y + 85

e x t re m e 1. 3^{x}

e x t re m e f (x) = x^{3} - 2 x^{2} - 15 x + 5, - 2 \leq x \leq 0