extreme f(x)=(x^2-10x+25)/(x-8)

Lösung

extrempunkte

f (x) = \frac{x ^{2} - 10 x + 25}{x - 8}

Maximum (5, 0), Minimum (11, 12)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} - 16 x + 55}{( x - 8 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < 5,

Absteigend

: 5 < x < 8,

Absteigend

: 8 < x < 11,

Ansteigend

: 11 < x < \infty

Stecke

x = 5

\frac{x ^{2} - 10 x + 25}{x - 8} : 0

Maximum (5, 0)

Stecke

x = 11

\frac{x ^{2} - 10 x + 25}{x - 8} : 12

Minimum (11, 12)

Maximum (5, 0), Minimum (11, 12)

e x t re m e y = x - 2 cos (x), 0 \leq x \leq 2 π

e x t re m e f (x, y) = 11 x^{3} - 33 x y + 11 y^{3}

e x t re m e f (x) = x^{3} + y^{2} - 3 x^{2} - 3 y^{2} - 9 x

e x t re m e f (x) = - 6 x^{3} + 18 x^{2} + 54 x - 72

e x t re m e f (x) = I n (x + 1 + x^{2})