extreme f(x)=2x^3-3x^2-252x

Lösung

extrempunkte

f (x) = 2 x^{3} - 3 x^{2} - 252 x

Maximum (- 6, 972), Minimum (7, - 1225)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 6 x - 252

Intervalle finden:

Ansteigend

: - \infty < x < - 6,

Absteigend

: - 6 < x < 7,

Ansteigend

: 7 < x < \infty

Stecke

x = - 6

2 x^{3} - 3 x^{2} - 252 x : 972

Maximum (- 6, 972)

Stecke

x = 7

2 x^{3} - 3 x^{2} - 252 x : - 1225

Minimum (7, - 1225)

Maximum (- 6, 972), Minimum (7, - 1225)

e x t re m e 4 a p + 50 p - 9 p^{2} - \frac{1}{10} a^{2} p - 110

e x t re m e f (x, y) = x^{3} y + 12 y x^{2} - 8 y

e x t re m e - 0.015 x^{2} + 1.24 x - 7.4

e x t re m e f (x, y) = x^{2} + y^{2} - 10 x + 16 y - 6

e x t re m e f (x) = \frac{x ^{4}}{4} - (\frac{x}{3})^{3} - x^{2} + 1