extreme f(x)=x[18-2(x)]^2

Lösung

extrempunkte

f (x) = x [18 - 2 (x)]^{2}

Maximum (3, 432), Minimum (9, 0)

Schritte zur Lösung

f^{'} (x) = 12 (x - 9) (x - 3)

Intervalle finden:

Ansteigend

: - \infty < x < 3,

Absteigend

: 3 < x < 9,

Ansteigend

: 9 < x < \infty

Stecke

x = 3

x [18 - 2 x]^{2} : 432

Maximum (3, 432)

Stecke

x = 9

x [18 - 2 x]^{2} : 0

Minimum (9, 0)

Maximum (3, 432), Minimum (9, 0)

e x t re m e f (x, y) = x^{2} - 3 y^{2} - 8 x + 9 y + 3 x y

e x t re m e f (d, y) = \frac{d}{d ^{2}} (y)

e x t re m e y = - 5 cos (3 x) - 2

e x t re m e f (x, y) = 3 x^{\frac{1}{3}} y^{\frac{1}{3}}

e x t re m e f (x) = \frac{x ^{2}}{x - 1}