monotone x^3-x^2-4x

Lösung

monotone intervalle

x^{3} - x^{2} - 4 x

Ansteigend : - \infty < x < \frac{- 13 + 1}{3}, Absteigend : \frac{- 13 + 1}{3} < x < \frac{13 + 1}{3}, Ansteigend : \frac{13 + 1}{3} < x < \infty

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 2 x - 4

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 13 + 1}{3},

Absteigend

: \frac{- 13 + 1}{3} < x < \frac{13 + 1}{3},

Ansteigend

: \frac{13 + 1}{3} < x < \infty

Ansteigend : - \infty < x < \frac{- 13 + 1}{3}, Absteigend : \frac{- 13 + 1}{3} < x < \frac{13 + 1}{3}, Ansteigend : \frac{13 + 1}{3} < x < \infty

s l o p e in t erce pt y = - 3 x + 3

d o main f (x) = 7 x + 20

in t erce pt s f (x) = 9 x - 7 y = 14

d o main f (x) = 4 (1.5)^{x} - 3

e x t re m e f (x) = - x^{3} + 2 x^{2} + 15 x - 5