extreme f(x)=x^2+10x^{2/3}

解答

极值点

f (x) = x^{2} + 10 x^{\frac{2}{3}}

极小值 (0, 0)

求解步骤

f^{'} (x) = \frac{20 + 6 x ^{\frac{4}{3}}}{3 x ^{\frac{1}{3}}}

Find intervals:

递减

: - \infty < x < 0,

递增

: 0 < x < \infty

将

x = 0

代入

x^{2} + 10 x^{\frac{2}{3}} : 0

极小值 (0, 0)

e x t re m e y = - x^{2} + 1 -, 1 \leq x \leq 2

e x t re m e f (x) = 3 x^{4} - 12 x^{3} - 60 x^{2} + 4

e x t re m e f (x) = 13 e^{- x}

e x t re m e f (x) = - x^{4} - 6 x

e x t re m e P (X, Y) = 36 X^{2} - 9 Y^{2}