extreme f(x)=-0.3t^2+2.4t+98.2

解答

极值点

f (x) = - 0.3 t^{2} + 2.4 t + 98.2

极大值 (4, 103)

求解步骤

f^{'} (t) = - 0.6 t + 2.4

Find intervals:

递增

: - \infty < t < 4,

递减

: 4 < t < \infty

将

t = 4

代入

- 0.3 t^{2} + 2.4 t + 98.2 : 103

极大值 (4, 103)

e x t re m e f (x) = \frac{( x ^{2} - 8 )}{( x - 3 )}

e x t re m e f (x) = 4.3 x - 0.01 x^{2} - 8

e x t re m e f (x) = x^{5} - 3125 x, - 7 \leq x \leq 7

e x t re m e \frac{- 2 ln ( x ) - 2}{x ^{2}}

e x t re m e f (x) = x^{2} + \frac{200}{x}, [0, \infty]