mittelpunkt (6,-3),(7,-2)

Lösung

mittelpunkt

(6, - 3), (7, - 2)

(\frac{13}{2}, - \frac{5}{2})

Schritte zur Lösung

Mittelpunkt von

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (6, - 3), (x_{2}, y_{2}) = (7, - 2)

= (\frac{7 + 6}{2}, \frac{- 2 - 3}{2})

Fasse zusammen

= (\frac{13}{2}, - \frac{5}{2})

d o main f (x) = \frac{5 - 4 x - x ^{2}}{x + 3}

sy mm e t ry - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

p a r i t y f (x) = sin (ln (- \frac{3}{2}))

in t erce pt s f (x) = \frac{6 x}{x ^{2} + 16}

a sy m pt o t es f (x) = \frac{x ^{2} - x}{- x + 1}