extreme f(x)=x^3-5x^2-8x+4

Lösung

extrempunkte

f (x) = x^{3} - 5 x^{2} - 8 x + 4

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 10 x - 8

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < 4,

Ansteigend

: 4 < x < \infty

Stecke

x = - \frac{2}{3}

x^{3} - 5 x^{2} - 8 x + 4 : \frac{184}{27}

Maximum (- \frac{2}{3}, \frac{184}{27})

Stecke

x = 4

x^{3} - 5 x^{2} - 8 x + 4 : - 44

Minimum (4, - 44)

Maximum (- \frac{2}{3}, \frac{184}{27}), Minimum (4, - 44)

a sy m pt o t es f (x) = \frac{x ( x + 3 )}{x ^{2} + x - 6}

in v erse \frac{- x - 3}{x + 2}

p a r i t y f (x) = 5 - 3 x

d o main - \frac{1}{2 6 - x}

cr i t i c a l f (x) = 9 x^{2} - x^{3} - 3