inflection f(x)=x^3-4x^2+5x-2

Lösung

wendepunkte

f (x) = x^{3} - 4 x^{2} + 5 x - 2

(\frac{4}{3}, - \frac{2}{27})

Schritte zur Lösung

f^{''} (x) = 6 x - 8

Intervalle finden:

Konkav fallend

: - \infty < x < \frac{4}{3},

Konkav steigend

: \frac{4}{3} < x < \infty

Stecke

x = \frac{4}{3}

x^{3} - 4 x^{2} + 5 x - 2 : - \frac{2}{27}

(\frac{4}{3}, - \frac{2}{27})

d o main \frac{x - 4}{x + 7}

y = x^{2} + 3

a sy m pt o t es f (x) = \frac{x ^{2} + 4 x}{x + 4}

cr i t i c a l f (t) = t^{4} - 20 t^{3} + 112 t^{2}

d o main f (x) = \frac{x}{x ^{2} - 16 x + 48}