What is the critical f(x)=5x^4+8x^3+2x^2 ?

The critical f(x)=5x^4+8x^3+2x^2 is x=-1,x=-1/5 ,x=0

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critical f(x)=5x^4+8x^3+2x^2

critical points

f (x) = 5 x^{4} + 8 x^{3} + 2 x^{2}

x = - 1, x = - \frac{1}{5}, x = 0

Solution steps

5 x^{4} + 8 x^{3} + 2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = - \frac{1}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 x^{4} + 8 x^{3} + 2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = - \frac{1}{5}, x = 0

sy mm e t ry y (X) = - X^{2}

d o main f (x) = \frac{7 x - 5}{7 x}

a sy m pt o t es f (x) = 3 x - 1

cr i t i c a l 3 t^{2} - \frac{1}{t ^{2}}

in v erse f (x) = x^{\frac{3}{2}}

What is the critical f(x)=5x^4+8x^3+2x^2 ?
The critical f(x)=5x^4+8x^3+2x^2 is x=-1,x=-1/5 ,x=0