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Popular >

midpoint (9,-3),(-2,-2)

Solution

midpoint

(9, - 3), (- 2, - 2)

Solution

(\frac{7}{2}, - \frac{5}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (9, - 3), (x_{2}, y_{2}) = (- 2, - 2)

= (\frac{- 2 + 9}{2}, \frac{- 2 - 3}{2})

Refine

= (\frac{7}{2}, - \frac{5}{2})

Popular Examples

parity 2x^2-x-1 parity

2 x^{2} - x - 1

domain of sqrt(2-x/(x-3))domain

2 - \frac{x}{x - 3}

asymptotes of f(x)=(x^2-49)/(x(x-7))asymptotes

f (x) = \frac{x ^{2} - 49}{x ( x - 7 )}

domain of f(x)=x^2+8x domain

f (x) = x^{2} + 8 x

inverse of y=4x-3 inverse

y = 4 x - 3

Frequently Asked Questions (FAQ)

What is the midpoint (9,-3),(-2,-2) ?
The midpoint (9,-3),(-2,-2) is (7/2 ,-5/2)