变换-3/2 cos(3x-1/2)+2

解答

变换

- \frac{3}{2} cos (3 x - \frac{1}{2}) + 2

相位 : \frac{1}{6}, 垂直 : 2

求解步骤

f (x) = - \frac{3}{2} cos (3 x - \frac{1}{2}) + 2

g (B x - C) = cos (3 x - \frac{1}{2}), B = 3, C = \frac{1}{2}, D = 2

因此，相位变换

\frac{C}{B}

为

\frac{\frac{1}{2}}{3}

\frac{1}{6}

垂直变换

D

为

2

2

a sy m pt o t es f (x) = \frac{x ^{4} - 324}{x ^{2} - 18}

d o main f (x) = \frac{x ^{2}}{x ^{2} + 9}

in v erse f (x) = e^{y - 1}

e x t re m e f (x) = \frac{6 x - 10}{x ^{2} - 1}

in v erse f (x) = \frac{3}{7} x - 6