值域-2(1/3)^x

解答

值域

- 2 (\frac{1}{3})^{x}

f (x) < 0

间隔符号

(- \infty, 0)

求解步骤

- c \cdot n^{a x + b} + k

形式的指数函数的值域为

f (x) < k

k = 0

f (x) < 0

d o main f (x) = \frac{6 x}{x ^{2} + 5}

in f l ec t i o n f (x) = x^{5} - 5 x^{4} + 15 x + 4

in v erse f (x) = \frac{( x + 11 )}{x - 8}

in v erse f (x) = (x - 2)^{2} + 4

in v erse f (x) = - \frac{2}{x - 3}