What is the shift f(x)=cos(x+pi)-1 ?

The shift f(x)=cos(x+pi)-1 is Phase:-pi, Vertical:-1

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shift f(x)=cos(x+pi)-1

shift

f (x) = cos (x + π) - 1

Phase : - π, Vertical : - 1

Solution steps

f (x) = cos (x + π) - 1

g (B x - C) = cos (x + π), B = 1, C = - π, D = - 1

Therefore, the phase shift

\frac{C}{B}

\frac{- π}{1}

- π

The vertical shift

D

- 1

- 1

f (x) = \frac{2}{3} x^{3} - 4 x

\frac{\frac{x}{x + 9}}{\frac{x}{x + 9} + 9}

f (x) = (\frac{5}{4})^{- x}

f (x) = 8 - x

f (x) = 16 - (12 x + 8)^{2}

What is the shift f(x)=cos(x+pi)-1 ?
The shift f(x)=cos(x+pi)-1 is Phase:-pi, Vertical:-1