What is the range of 2/3 sqrt(x+6)-2 ?

The range of 2/3 sqrt(x+6)-2 is f(x)>=-2

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range of 2/3 sqrt(x+6)-2

range

\frac{2}{3} x + 6 - 2

f (x) \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = - 2

f (x) \geq - 2

f (x) = sin (x) cos (x)

g (x) = 3^{x - 3}

x^{2} - 8

f (x) = - 3 (x - 1)^{2} - 9

f (x) = (\frac{1}{3})^{x}