extreme y=390x-0.25x^3

Lösung

extrempunkte

y = 390 x - 0.25 x^{3}

Minimum (- 2130, - 5928.91221 \dots), Maximum (2130, 5928.91221 \dots)

Schritte zur Lösung

f^{'} (x) = 390 - 0.75 x^{2}

Intervalle finden:

Absteigend

: - \infty < x < - 2130,

Ansteigend

: - 2130 < x < 2130,

Absteigend

: 2130 < x < \infty

Stecke

x = - 2130

390 x - 0.25 x^{3} : - 5928.91221 \dots

Minimum (- 2130, - 5928.91221 \dots)

Stecke

x = 2130

390 x - 0.25 x^{3} : 5928.91221 \dots

Maximum (2130, 5928.91221 \dots)

Minimum (- 2130, - 5928.91221 \dots), Maximum (2130, 5928.91221 \dots)

d o main f (x) = \frac{1 - 5 x}{3 x - 4}

l in e m = 1, (- 1, - 11)

d o main f (x) = 3 (1 - t)^{2} - 2 (1 - t) + 5

in t erce pt s F (x) = (x + 3)^{2} (x - 2)

m o n o t o n e (x - 2)^{3}