What is the perpendicular y= 3/4 x+5,(3,-3) ?

The perpendicular y= 3/4 x+5,(3,-3) is y=-4/3 x+1

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perpendicular y= 3/4 x+5,(3,-3)

perpendicular

y = \frac{3}{4} x + 5, (3, - 3)

y = - \frac{4}{3} x + 1

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{4} x + 5

that passes through

(3, - 3)

Find the slope of

y = \frac{3}{4} x + 5 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(3, - 3) : y = - \frac{4}{3} x + 1

y = - \frac{4}{3} x + 1

f (x) = 25 - x^{2}

f (x) = 4 - x

f (x) = x^{3} + 5 x - 2

y = f (x) = ln (x + 4 + x^{2})

f (x) = x (e^{\frac{( - x ^{2} )}{8}})

What is the perpendicular y= 3/4 x+5,(3,-3) ?
The perpendicular y= 3/4 x+5,(3,-3) is y=-4/3 x+1