What is the inverse of f(x)=x^2+5,x>= 0 ?

The inverse of f(x)=x^2+5,x>= 0 is sqrt(x-5),-sqrt(x-5)

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inverse of f(x)=x^2+5,x>= 0

inverse

f (x) = x^{2} + 5, x \geq 0

x - 5, - x - 5

Solution steps

y = x^{2} + 5

Replace

x

with

y

x = y^{2} + 5

Solve for

y, x = y^{2} + 5

x - 5, - x - 5

f (x) = 5 csc (\frac{1}{3} x) - 1

(1, 2), (5, 6)

\frac{2}{x - 2} - 8

\frac{3}{x + 2} - x - 3

ln (x - 1) - 1

What is the inverse of f(x)=x^2+5,x>= 0 ?
The inverse of f(x)=x^2+5,x>= 0 is sqrt(x-5),-sqrt(x-5)