extreme-t^3+21t^2+35t+20

Lösung

extrempunkte

- t^{3} + 21 t^{2} + 35 t + 20

Minimum (- \frac{- 21 + 546}{3}, \frac{518 546 - 12348}{9} + 2323 - 98546), Maximum (\frac{21 + 546}{3}, \frac{- 12348 - 518 546}{9} + 2323 + 98546)

Schritte zur Lösung

f^{'} (t) = - 3 t^{2} + 42 t + 35

Intervalle finden:

Absteigend

: - \infty < t < - \frac{182}{3} + 7,

Ansteigend

: - \frac{182}{3} + 7 < t < \frac{182}{3} + 7,

Absteigend

: \frac{182}{3} + 7 < t < \infty

Stecke

t = - \frac{- 21 + 546}{3}

- t^{3} + 21 t^{2} + 35 t + 20 : \frac{518 546 - 12348}{9} + 2323 - 98546

Minimum (- \frac{- 21 + 546}{3}, \frac{518 546 - 12348}{9} + 2323 - 98546)

Stecke

t = \frac{21 + 546}{3}

- t^{3} + 21 t^{2} + 35 t + 20 : \frac{- 12348 - 518 546}{9} + 2323 + 98546

Maximum (\frac{21 + 546}{3}, \frac{- 12348 - 518 546}{9} + 2323 + 98546)

Minimum (- \frac{- 21 + 546}{3}, \frac{518 546 - 12348}{9} + 2323 - 98546), Maximum (\frac{21 + 546}{3}, \frac{- 12348 - 518 546}{9} + 2323 + 98546)

in v erse f (y) = 2 x + 3

r an g e 6 x^{2} - 15 x

e x t re m e f (x) = x (x^{2} - 6 x + 9)

p a r i t y y = \frac{1 - x}{cos ( x )}

am pl i t u d e - sin (2 x)