What is the inverse of f(x)=log_{5}(((1-x))/(1+x)) ?

The inverse of f(x)=log_{5}(((1-x))/(1+x)) is (1-5^x)/(5^x+1)

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inverse of f(x)=log_{5}(((1-x))/(1+x))

inverse

f (x) = lo g_{5} (\frac{( 1 - x )}{1 + x})

\frac{1 - 5 ^{x}}{5 ^{x} + 1}

Solution steps

y = lo g_{5} (\frac{1 - x}{1 + x})

Replace

x

with

y

x = lo g_{5} (\frac{1 - y}{1 + y})

Solve for

y, x = lo g_{5} (\frac{1 - y}{1 + y})

\frac{1 - 5 ^{x}}{5 ^{x} + 1}

d o main (2 - x^{2}) - (x^{2} - 9)

cr i t i c a l f (x) = (x - 2)^{\frac{6}{7}}

r an g e - cos (2 x)

s l o p e y = - \frac{4}{5} x + \frac{1}{2}

d i s t an ce (- 1, 8), (2, 3)

What is the inverse of f(x)=log_{5}(((1-x))/(1+x)) ?
The inverse of f(x)=log_{5}(((1-x))/(1+x)) is (1-5^x)/(5^x+1)