What is the domain of y=sqrt(2x-10) ?

The domain of y=sqrt(2x-10) is x>= 5

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domain of y=sqrt(2x-10)

domain

y = 2 x - 10

x \geq 5

Interval Notation

[5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

The function domain

x \geq 5

(- 6, - 3), (- 1, 9)

f (x) = x - \frac{27 x}{x + 3}

- 7 x - 2 y = - 8

f (x) = \frac{- 5 x + 5}{3 x + 1}

f (x) = \frac{x ^{2} + 3 x + 2}{x + 2}